The blog talks about variety of topics on Embedded System, 8085 microprocessor, 8051 microcontroller, ARM Architecture, C2000 Architecture, C28x, AVR and many many more. Also includes some projects that have been worked upon and also episodes to Embedded System Podcast.
The lower address of 01H will be replaced by 50H and higher address by 20H....
Point to remember: Program and Data Memory are two different things... If program is there at 2050H Data cannot be stored there... This is based on assumption that you are talking about clash of memory (as 2050 we are fetching opcode in this diagram)
In lda why we didn't use ta memory read in the 2nd and 3rd machine cycle.........bcoz I m confused ......... In the case of lda we write from memory to accumulator..........
for the LDA instruction i need to load/store contents to the accumulator how can we achieve it by using a read cycle at the last as the address is that of the operand.
There is only one difference In STA the data is written hence WR(bar) is set to low. In LDA the WR(bar) will remain high and the RD will be set to high indicating that the data has been read.
well
ReplyDeletewhere is CLK?
ReplyDeleteThe columns T1 T2 .... T13 are cycles....
DeleteThe clock is in the wall of our house :p Kidding :D
Deletethank you,it was very useful..
ReplyDeleteYou are msot welcome.....
DeleteKeep visiting...
in lda there will be opcode fetch memory read memory read and again memory? please clarify me.
ReplyDeleteLDA is a 16 bit loading instruction.
DeleteWhereas each memory address stores only 8 bit of data
So to get 16 bit of data memory has to be read twice.
I think this is wrong. Its the 16bit addres which takes 2 read n one 8bit data in that address that takes 1 read cycles
DeleteYES,DATA IS 8 BIT ONLY BUT TO GET THE MEMORY LOCATION WHERE DATA IS STORED WE REQUIRE TWO READ MACHINE CYCLES.
DeleteThis comment has been removed by the author.
Deletetiming diagram for LDA 2050H
ReplyDeleteThe lower address of 01H will be replaced by 50H and higher address by 20H....
DeletePoint to remember: Program and Data Memory are two different things...
If program is there at 2050H Data cannot be stored there...
This is based on assumption that you are talking about clash of memory (as 2050 we are fetching opcode in this diagram)
THANK YOU! IT WAS GREAT HELP!
ReplyDeleteYou are welcome Keep visiting...
DeleteTHANK YOU! IT WAS GREAT HELP!
ReplyDeleteYou are welcome Keep visiting...
Deletethanks
ReplyDeleteYou are welcome Keep visiting...
Deletehlw
ReplyDeleteIn lda why we didn't use ta memory read in the 2nd and 3rd machine cycle.........bcoz I m confused ......... In the case of lda we write from memory to accumulator..........
ReplyDeleteDraw the timing diagram for CALL 2500H and Calculate execution time with T-state and Machine
ReplyDeletecycle. Assume clock frequency 3MHz..... answer ???
that last one is WB or it should be WR(bar). and in LDA we don't need that last step. right?
ReplyDeleteIt is WR(bar) you can see once you zoom. No in LDA last step is not required. It is required in STA.
DeleteIn LDA what it does in last memory read operation ?
ReplyDeleteIn last memory read operation it takes in the DATA into the accumnulator.
DeleteSir will the above timing diagram be same for LDA F050H
ReplyDeleteTq
ReplyDeletefor the LDA instruction i need to load/store contents to the accumulator how can we achieve it by using a read cycle at the last as the address is that of the operand.
ReplyDeleteq
ReplyDeleteTime diagram of sta and lda are basically same???
ReplyDeleteThere is only one difference
DeleteIn STA the data is written hence WR(bar) is set to low.
In LDA the WR(bar) will remain high and the RD will be set to high indicating that the data has been read.
what is the timing diagram of this instruction 67AD: LDA 9E94h
ReplyDelete